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# Copyright (c) 2003-2016 CORE Security Technologies
#
# This software is provided under under a slightly modified version
# of the Apache Software License. See the accompanying LICENSE file
# for more information.
#
# Description:
# Generate UUID compliant with http://www.webdav.org/specs/draft-leach-uuids-guids-01.txt.
# A different, much simpler (not necessarily better) algorithm is used.
#
# Author:
# Javier Kohen (jkohen)
#
import re
from random import randrange
from struct import pack, unpack
try:
long # Python 2
except NameError:
long = int # Python 3
def generate():
# UHm... crappy Python has an maximum integer of 2**31-1.
top = (1<<31)-1
return pack("IIII", randrange(top), randrange(top), randrange(top), randrange(top))
def bin_to_string(uuid):
uuid1, uuid2, uuid3 = unpack('<LHH', uuid[:8])
uuid4, uuid5, uuid6 = unpack('>HHL', uuid[8:16])
return '%08X-%04X-%04X-%04X-%04X%08X' % (uuid1, uuid2, uuid3, uuid4, uuid5, uuid6)
def string_to_bin(uuid):
matches = re.match('([\dA-Fa-f]{8})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})([\dA-Fa-f]{8})', uuid)
(uuid1, uuid2, uuid3, uuid4, uuid5, uuid6) = map(lambda x: long(x, 16), matches.groups())
uuid = pack('<LHH', uuid1, uuid2, uuid3)
uuid += pack('>HHL', uuid4, uuid5, uuid6)
return uuid
def stringver_to_bin(s):
(maj,min) = s.split('.')
return pack('<H',int(maj)) + pack('<H',int(min))
def uuidtup_to_bin(tup):
if len(tup) != 2: return
return string_to_bin(tup[0]) + stringver_to_bin(tup[1])
def bin_to_uuidtup(bin):
assert len(bin) == 20
uuidstr = bin_to_string(bin[:16])
maj, min = unpack("<HH", bin[16:])
return uuidstr, "%d.%d" % (maj, min)
#input: string
#output: tuple (uuid,version)
#if version is not found in the input string "1.0" is returned
#example:
# "00000000-0000-0000-0000-000000000000 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0')
# "10000000-2000-3000-4000-500000000000 version 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0')
# "10000000-2000-3000-4000-500000000000 v 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0')
# "10000000-2000-3000-4000-500000000000" returns ('00000000-0000-0000-0000-000000000000','1.0')
def string_to_uuidtup(s):
g = re.search("([A-Fa-f0-9]{8}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{12}).*?([0-9]{1,5}\.[0-9]{1,5})",s+" 1.0")
if g:
(u,v) = g.groups()
return (u,v)
return
def uuidtup_to_string(tup):
uuid, (maj, min) = tup
return "%s v%d.%d" % (uuid, maj, min)
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